求助，用linux基本命令提取json参数

椎名***

1. {"status":{"code":"1","message":"\u64cd\u4f5c\u5df2\u7ecf\u6210\u529f\u5b8c\u6210","created_at":"2020-06-22 15:49:30"},"domain":{"id":12121212,"name":"sh.club","punycode":"sh.club","grade":"DP_Free","owner":"qcloud_uin_****@qcloud.com","ext_status":"","ttl":600,"min_ttl":600,"dnspod_ns":["f1g1ns1.dnspod.net","f1g1ns2.dnspod.net"],"status":"enable"},"info":{"sub_domains":"4","record_total":"4","records_num":"4"},"records":[{"id":"1247459","ttl":"86400","value":"f1g1ns1.dnspod.net.","enabled":"1","status":"enable","updated_on":"2020-05-30 22:32:27","name":"@","line":"\u9ed8\u8ba4","line_id":"0","type":"NS","weight":null,"monitor_status":"","remark":"","use_aqb":"no","mx":"0","hold":"hold"},{"id":"51473","ttl":"86400","value":"f1g1ns2.dnspod.net.","enabled":"1","status":"enable","updated_on":"2020-05-30 22:32:27","name":"@","line":"\u9ed8\u8ba4","line_id":"0","type":"NS","weight":null,"monitor_status":"","remark":"","use_aqb":"no","mx":"0","hold":"hold"},{"id":"123456","ttl":"600","value":"2409::e9e","enabled":"1","status":"enable","updated_on":"2020-06-22 15:40:14","name":"@","line":"\u9ed8\u8ba4","line_id":"0","type":"AAAA","weight":null,"monitor_status":"","remark":"","use_aqb":"no","mx":"0"},{"id":"654321","ttl":"10","value":"10.0.0.1","enabled":"0","status":"disable","updated_on":"2020-06-21 11:13:43","name":"@","line":"\u9ed8\u8ba4","line_id":"0","type":"A","weight":null,"monitor_status":"","remark":"","use_aqb":"no","mx":"0"}]}

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这是腾讯云的dns的json，我想提取我ipv6的record_id，但是用了几个脚本都不好用。学习了正则表达式，还是不会写。要求就是只能用openwrt的基本命令，不能使用扩展命令


顺便问下linux大佬

1. sed 's/.*"id":"\([0-9]*\)".*/\1/'

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为什么这个只能匹配最后一个id

kong***

你需要一个 jsonfilter

fb***

sed 's/.*"id":"\([0-9]*\)".*/\1/g'

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fbbyy 发表于 2020-6-22 16:43
sed 's/.*"id":"\([0-9]*\)".*/\1/g'

你这个和我的没区别

tqw***

不晓得怎么用，看看。。学习

wuli***

"需要转义，麻鬼烦，反正运算是CPU的事，多几个步骤总好过想死脑细胞，所以用最蠢的办法：
sed 's/"/ /g'|egrep -o ' id : [0-9]*'|awk -F ' : ' '{print $2}'

椎名***

1. sed 's/"id":"([0-9]*)","ttl":"[0-9]{3,4}".*"type":"AAAA"/\1/'

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这样子就没问题